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4(3-2x)=5(3x+1)
We move all terms to the left:
4(3-2x)-(5(3x+1))=0
We add all the numbers together, and all the variables
4(-2x+3)-(5(3x+1))=0
We multiply parentheses
-8x-(5(3x+1))+12=0
We calculate terms in parentheses: -(5(3x+1)), so:We get rid of parentheses
5(3x+1)
We multiply parentheses
15x+5
Back to the equation:
-(15x+5)
-8x-15x-5+12=0
We add all the numbers together, and all the variables
-23x+7=0
We move all terms containing x to the left, all other terms to the right
-23x=-7
x=-7/-23
x=7/23
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