4(3-2x)=6(x+1)

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Solution for 4(3-2x)=6(x+1) equation:



4(3-2x)=6(x+1)
We move all terms to the left:
4(3-2x)-(6(x+1))=0
We add all the numbers together, and all the variables
4(-2x+3)-(6(x+1))=0
We multiply parentheses
-8x-(6(x+1))+12=0
We calculate terms in parentheses: -(6(x+1)), so:
6(x+1)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
We get rid of parentheses
-8x-6x-6+12=0
We add all the numbers together, and all the variables
-14x+6=0
We move all terms containing x to the left, all other terms to the right
-14x=-6
x=-6/-14
x=3/7

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