4(3-2x)=7-(6x+1)

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Solution for 4(3-2x)=7-(6x+1) equation: 



4(3-2x)=7-(6x+1)

We move all terms to the left:

4(3-2x)-(7-(6x+1))=0

We add all the numbers together, and all the variables

4(-2x+3)-(7-(6x+1))=0

We multiply parentheses

-8x-(7-(6x+1))+12=0



We calculate terms in parentheses: -(7-(6x+1)), so:

7-(6x+1)

determiningTheFunctionDomain
-(6x+1)+7

We get rid of parentheses

-6x-1+7

We add all the numbers together, and all the variables

-6x+6

Back to the equation:

-(-6x+6)



We get rid of parentheses

-8x+6x-6+12=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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