4(3-5a)+7=7(5-4a)

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Solution for 4(3-5a)+7=7(5-4a) equation: 



4(3-5a)+7=7(5-4a)

We move all terms to the left:

4(3-5a)+7-(7(5-4a))=0

We add all the numbers together, and all the variables

4(-5a+3)-(7(-4a+5))+7=0

We multiply parentheses

-20a-(7(-4a+5))+12+7=0



We calculate terms in parentheses: -(7(-4a+5)), so:

7(-4a+5)

We multiply parentheses

-28a+35

Back to the equation:

-(-28a+35)



We add all the numbers together, and all the variables

-20a-(-28a+35)+19=0

We get rid of parentheses

-20a+28a-35+19=0

We add all the numbers together, and all the variables

8a-16=0

We move all terms containing a to the left, all other terms to the right

8a=16

a=16/8

a=2

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