4(3-5x)+8x=3(1-3x)+6x

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Solution for 4(3-5x)+8x=3(1-3x)+6x equation: 



4(3-5x)+8x=3(1-3x)+6x

We move all terms to the left:

4(3-5x)+8x-(3(1-3x)+6x)=0

We add all the numbers together, and all the variables

4(-5x+3)+8x-(3(-3x+1)+6x)=0

We add all the numbers together, and all the variables

8x+4(-5x+3)-(3(-3x+1)+6x)=0

We multiply parentheses

8x-20x-(3(-3x+1)+6x)+12=0



We calculate terms in parentheses: -(3(-3x+1)+6x), so:

3(-3x+1)+6x

We add all the numbers together, and all the variables

6x+3(-3x+1)

We multiply parentheses

6x-9x+3

We add all the numbers together, and all the variables

-3x+3

Back to the equation:

-(-3x+3)



We add all the numbers together, and all the variables

-12x-(-3x+3)+12=0

We get rid of parentheses

-12x+3x-3+12=0

We add all the numbers together, and all the variables

-9x+9=0

We move all terms containing x to the left, all other terms to the right

-9x=-9

x=-9/-9

x=1

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