4(3-b)-32=26b-5(4+6b)

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Solution for 4(3-b)-32=26b-5(4+6b) equation: 



4(3-b)-32=26b-5(4+6b)

We move all terms to the left:

4(3-b)-32-(26b-5(4+6b))=0

We add all the numbers together, and all the variables

4(-1b+3)-(26b-5(6b+4))-32=0

We multiply parentheses

-4b-(26b-5(6b+4))+12-32=0



We calculate terms in parentheses: -(26b-5(6b+4)), so:

26b-5(6b+4)

We multiply parentheses

26b-30b-20

We add all the numbers together, and all the variables

-4b-20

Back to the equation:

-(-4b-20)



We add all the numbers together, and all the variables

-4b-(-4b-20)-20=0

We get rid of parentheses

-4b+4b+20-20=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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