4(3-c)+5c+3=6c-20

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Solution for 4(3-c)+5c+3=6c-20 equation: 


Simplifying
4(3 + -1c) + 5c + 3 = 6c + -20
(3 * 4 + -1c * 4) + 5c + 3 = 6c + -20
(12 + -4c) + 5c + 3 = 6c + -20

Reorder the terms:
12 + 3 + -4c + 5c = 6c + -20

Combine like terms: 12 + 3 = 15
15 + -4c + 5c = 6c + -20

Combine like terms: -4c + 5c = 1c
15 + 1c = 6c + -20

Reorder the terms:
15 + 1c = -20 + 6c

Solving
15 + 1c = -20 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
15 + 1c + -6c = -20 + 6c + -6c

Combine like terms: 1c + -6c = -5c
15 + -5c = -20 + 6c + -6c

Combine like terms: 6c + -6c = 0
15 + -5c = -20 + 0
15 + -5c = -20

Add '-15' to each side of the equation.
15 + -15 + -5c = -20 + -15

Combine like terms: 15 + -15 = 0
0 + -5c = -20 + -15
-5c = -20 + -15

Combine like terms: -20 + -15 = -35
-5c = -35

Divide each side by '-5'.
c = 7

Simplifying
c = 7

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