4(3-c)-24=20c-(2+4c)

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Solution for 4(3-c)-24=20c-(2+4c) equation: 



4(3-c)-24=20c-(2+4c)

We move all terms to the left:

4(3-c)-24-(20c-(2+4c))=0

We add all the numbers together, and all the variables

4(-1c+3)-(20c-(4c+2))-24=0

We multiply parentheses

-4c-(20c-(4c+2))+12-24=0



We calculate terms in parentheses: -(20c-(4c+2)), so:

20c-(4c+2)

We get rid of parentheses

20c-4c-2

We add all the numbers together, and all the variables

16c-2

Back to the equation:

-(16c-2)



We add all the numbers together, and all the variables

-4c-(16c-2)-12=0

We get rid of parentheses

-4c-16c+2-12=0

We add all the numbers together, and all the variables

-20c-10=0

We move all terms containing c to the left, all other terms to the right

-20c=10

c=10/-20

c=-1/2

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