4(3-c)-32=26c-5(4+6c)

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Solution for 4(3-c)-32=26c-5(4+6c) equation: 



4(3-c)-32=26c-5(4+6c)

We move all terms to the left:

4(3-c)-32-(26c-5(4+6c))=0

We add all the numbers together, and all the variables

4(-1c+3)-(26c-5(6c+4))-32=0

We multiply parentheses

-4c-(26c-5(6c+4))+12-32=0



We calculate terms in parentheses: -(26c-5(6c+4)), so:

26c-5(6c+4)

We multiply parentheses

26c-30c-20

We add all the numbers together, and all the variables

-4c-20

Back to the equation:

-(-4c-20)



We add all the numbers together, and all the variables

-4c-(-4c-20)-20=0

We get rid of parentheses

-4c+4c+20-20=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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