4(3-u)+u=-4-12

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Solution for 4(3-u)+u=-4-12 equation:



4(3-u)+u=-4-12
We move all terms to the left:
4(3-u)+u-(-4-12)=0
We add all the numbers together, and all the variables
4(-1u+3)+u-(-16)=0
We add all the numbers together, and all the variables
u+4(-1u+3)+16=0
We multiply parentheses
u-4u+12+16=0
We add all the numbers together, and all the variables
-3u+28=0
We move all terms containing u to the left, all other terms to the right
-3u=-28
u=-28/-3
u=9+1/3

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