4(3-x)+6x=x+12-x

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Solution for 4(3-x)+6x=x+12-x equation: 



4(3-x)+6x=x+12-x

We move all terms to the left:

4(3-x)+6x-(x+12-x)=0

We add all the numbers together, and all the variables

4(-1x+3)+6x-12=0

We add all the numbers together, and all the variables

6x+4(-1x+3)-12=0

We multiply parentheses

6x-4x+12-12=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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