4(3-x)=2(x-4)

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Solution for 4(3-x)=2(x-4) equation: 



4(3-x)=2(x-4)

We move all terms to the left:

4(3-x)-(2(x-4))=0

We add all the numbers together, and all the variables

4(-1x+3)-(2(x-4))=0

We multiply parentheses

-4x-(2(x-4))+12=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We get rid of parentheses

-4x-2x+8+12=0

We add all the numbers together, and all the variables

-6x+20=0

We move all terms containing x to the left, all other terms to the right

-6x=-20

x=-20/-6

x=3+1/3

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