4(3-z)/3(7+z)=1/3

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Solution for 4(3-z)/3(7+z)=1/3 equation: 


z in (-oo:+oo)

((4*(3-z))/3)*(z+7) = 1/3 // - 1/3

((4*(3-z))/3)*(z+7)-(1/3) = 0

((4*(3-z))/3)*(z+7)-1/3 = 0

(4*(3-z)*(z+7))/3-1/3 = 0

4*(3-z)*(z+7)-1 = 0

83-4*z^2-16*z = 0

83-4*z^2-16*z = 0

83-4*z^2-16*z = 0

DELTA = (-16)^2-(-4*4*83)

DELTA = 1584

DELTA > 0

z = (1584^(1/2)+16)/(-4*2) or z = (16-1584^(1/2))/(-4*2)

z = (12*11^(1/2)+16)/(-8) or z = (16-12*11^(1/2))/(-8)

(z-((12*11^(1/2)+16)/(-8)))*(z-((16-12*11^(1/2))/(-8))) = 0

((z-((12*11^(1/2)+16)/(-8)))*(z-((16-12*11^(1/2))/(-8))))/3 = 0

((z-((12*11^(1/2)+16)/(-8)))*(z-((16-12*11^(1/2))/(-8))))/3 = 0 // * 3

(z-((12*11^(1/2)+16)/(-8)))*(z-((16-12*11^(1/2))/(-8))) = 0

( z-((12*11^(1/2)+16)/(-8)) )

z-((12*11^(1/2)+16)/(-8)) = 0 // + (12*11^(1/2)+16)/(-8)

z = (12*11^(1/2)+16)/(-8)

( z-((16-12*11^(1/2))/(-8)) )

z-((16-12*11^(1/2))/(-8)) = 0 // + (16-12*11^(1/2))/(-8)

z = (16-12*11^(1/2))/(-8)

z in { (12*11^(1/2)+16)/(-8), (16-12*11^(1/2))/(-8) }

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