4(3-z)=-5(2+3z)

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Solution for 4(3-z)=-5(2+3z) equation: 



4(3-z)=-5(2+3z)

We move all terms to the left:

4(3-z)-(-5(2+3z))=0

We add all the numbers together, and all the variables

4(-1z+3)-(-5(3z+2))=0

We multiply parentheses

-4z-(-5(3z+2))+12=0



We calculate terms in parentheses: -(-5(3z+2)), so:

-5(3z+2)

We multiply parentheses

-15z-10

Back to the equation:

-(-15z-10)



We get rid of parentheses

-4z+15z+10+12=0

We add all the numbers together, and all the variables

11z+22=0

We move all terms containing z to the left, all other terms to the right

11z=-22

z=-22/11

z=-2

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