4(3.14)r2=1476

Solution for 4(3.14)r2=1476 equation:

4(3.14)r2=1476

We move all terms to the left:

4(3.14)r2-(1476)=0

We multiply parentheses

12.56r^2-1476=0

a = 12.56; b = 0; c = -1476;
Δ = b2-4ac
Δ = 02-4·12.56·(-1476)
Δ = 74154.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{74154.24}}{2*12.56}=\frac{0-\sqrt{74154.24}}{25.12}
=-\frac{\sqrt{}}{25.12}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{74154.24}}{2*12.56}=\frac{0+\sqrt{74154.24}}{25.12}
=\frac{\sqrt{}}{25.12}
$