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4(3/4+1)=5-2(n-1/2)
We move all terms to the left:
4(3/4+1)-(5-2(n-1/2))=0
We add all the numbers together, and all the variables
-(5-2(+n-1/2))+4(3/4+1)=0
We add all the numbers together, and all the variables
-(5-2(+n-1/2))+1=0
We multiply all the terms by the denominator
-(5-2(+n-1+1*2))=0
We calculate terms in parentheses: -(5-2(+n-1+1*2)), so:We get rid of parentheses
5-2(+n-1+1*2)
determiningTheFunctionDomain -2(+n-1+1*2)+5
We add all the numbers together, and all the variables
-2(n+1)+5
We multiply parentheses
-2n-2+5
We add all the numbers together, and all the variables
-2n+3
Back to the equation:
-(-2n+3)
2n-3=0
We move all terms containing n to the left, all other terms to the right
2n=3
n=3/2
n=1+1/2
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