4(32-7)=65-3(4z-9)

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Solution for 4(32-7)=65-3(4z-9) equation: 



4(32-7)=65-3(4z-9)

We move all terms to the left:

4(32-7)-(65-3(4z-9))=0

We add all the numbers together, and all the variables

-(65-3(4z-9))+425=0



We calculate terms in parentheses: -(65-3(4z-9)), so:

65-3(4z-9)

determiningTheFunctionDomain
-3(4z-9)+65

We multiply parentheses

-12z+27+65

We add all the numbers together, and all the variables

-12z+92

Back to the equation:

-(-12z+92)



We get rid of parentheses

12z-92+425=0

We add all the numbers together, and all the variables

12z+333=0

We move all terms containing z to the left, all other terms to the right

12z=-333

z=-333/12

z=-27+3/4

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