4(33+f)=148

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Solution for 4(33+f)=148 equation:



4(33+f)=148
We move all terms to the left:
4(33+f)-(148)=0
We add all the numbers together, and all the variables
4(f+33)-148=0
We multiply parentheses
4f+132-148=0
We add all the numbers together, and all the variables
4f-16=0
We move all terms containing f to the left, all other terms to the right
4f=16
f=16/4
f=4

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