4(35t+10)=20(3t+22)

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Solution for 4(35t+10)=20(3t+22) equation:



4(35t+10)=20(3t+22)
We move all terms to the left:
4(35t+10)-(20(3t+22))=0
We multiply parentheses
140t-(20(3t+22))+40=0
We calculate terms in parentheses: -(20(3t+22)), so:
20(3t+22)
We multiply parentheses
60t+440
Back to the equation:
-(60t+440)
We get rid of parentheses
140t-60t-440+40=0
We add all the numbers together, and all the variables
80t-400=0
We move all terms containing t to the left, all other terms to the right
80t=400
t=400/80
t=5

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