4(35t+10)=20(3t+22)

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Solution for 4(35t+10)=20(3t+22) equation: 



4(35t+10)=20(3t+22)

We move all terms to the left:

4(35t+10)-(20(3t+22))=0

We multiply parentheses

140t-(20(3t+22))+40=0



We calculate terms in parentheses: -(20(3t+22)), so:

20(3t+22)

We multiply parentheses

60t+440

Back to the equation:

-(60t+440)



We get rid of parentheses

140t-60t-440+40=0

We add all the numbers together, and all the variables

80t-400=0

We move all terms containing t to the left, all other terms to the right

80t=400

t=400/80

t=5

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