4(3D-5)-18=2(2d+3)+18

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Solution for 4(3D-5)-18=2(2d+3)+18 equation: 



4(3-5)-18=2(2D+3)+18

We move all terms to the left:

4(3-5)-18-(2(2D+3)+18)=0

We add all the numbers together, and all the variables

-(2(2D+3)+18)-18+4(-2)=0

We add all the numbers together, and all the variables

-(2(2D+3)+18)-26=0



We calculate terms in parentheses: -(2(2D+3)+18), so:

2(2D+3)+18

We multiply parentheses

4D+6+18

We add all the numbers together, and all the variables

4D+24

Back to the equation:

-(4D+24)



We get rid of parentheses

-4D-24-26=0

We add all the numbers together, and all the variables

-4D-50=0

We move all terms containing D to the left, all other terms to the right

-4D=50

D=50/-4

D=-12+1/2

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