4(3a+1)+6=5+12a-5

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Solution for 4(3a+1)+6=5+12a-5 equation: 


Simplifying
4(3a + 1) + 6 = 5 + 12a + -5

Reorder the terms:
4(1 + 3a) + 6 = 5 + 12a + -5
(1 * 4 + 3a * 4) + 6 = 5 + 12a + -5
(4 + 12a) + 6 = 5 + 12a + -5

Reorder the terms:
4 + 6 + 12a = 5 + 12a + -5

Combine like terms: 4 + 6 = 10
10 + 12a = 5 + 12a + -5

Reorder the terms:
10 + 12a = 5 + -5 + 12a

Combine like terms: 5 + -5 = 0
10 + 12a = 0 + 12a
10 + 12a = 12a

Add '-12a' to each side of the equation.
10 + 12a + -12a = 12a + -12a

Combine like terms: 12a + -12a = 0
10 + 0 = 12a + -12a
10 = 12a + -12a

Combine like terms: 12a + -12a = 0
10 = 0

Solving
10 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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