4(3a+2)-7(2+a)=4(a-5)

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Solution for 4(3a+2)-7(2+a)=4(a-5) equation:


Simplifying
4(3a + 2) + -7(2 + a) = 4(a + -5)

Reorder the terms:
4(2 + 3a) + -7(2 + a) = 4(a + -5)
(2 * 4 + 3a * 4) + -7(2 + a) = 4(a + -5)
(8 + 12a) + -7(2 + a) = 4(a + -5)
8 + 12a + (2 * -7 + a * -7) = 4(a + -5)
8 + 12a + (-14 + -7a) = 4(a + -5)

Reorder the terms:
8 + -14 + 12a + -7a = 4(a + -5)

Combine like terms: 8 + -14 = -6
-6 + 12a + -7a = 4(a + -5)

Combine like terms: 12a + -7a = 5a
-6 + 5a = 4(a + -5)

Reorder the terms:
-6 + 5a = 4(-5 + a)
-6 + 5a = (-5 * 4 + a * 4)
-6 + 5a = (-20 + 4a)

Solving
-6 + 5a = -20 + 4a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4a' to each side of the equation.
-6 + 5a + -4a = -20 + 4a + -4a

Combine like terms: 5a + -4a = 1a
-6 + 1a = -20 + 4a + -4a

Combine like terms: 4a + -4a = 0
-6 + 1a = -20 + 0
-6 + 1a = -20

Add '6' to each side of the equation.
-6 + 6 + 1a = -20 + 6

Combine like terms: -6 + 6 = 0
0 + 1a = -20 + 6
1a = -20 + 6

Combine like terms: -20 + 6 = -14
1a = -14

Divide each side by '1'.
a = -14

Simplifying
a = -14

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