4(3a+5)=16a+56-4(2a-1)

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Solution for 4(3a+5)=16a+56-4(2a-1) equation: 



4(3a+5)=16a+56-4(2a-1)

We move all terms to the left:

4(3a+5)-(16a+56-4(2a-1))=0

We multiply parentheses

12a-(16a+56-4(2a-1))+20=0



We calculate terms in parentheses: -(16a+56-4(2a-1)), so:

16a+56-4(2a-1)

determiningTheFunctionDomain
16a-4(2a-1)+56

We multiply parentheses

16a-8a+4+56

We add all the numbers together, and all the variables

8a+60

Back to the equation:

-(8a+60)



We get rid of parentheses

12a-8a-60+20=0

We add all the numbers together, and all the variables

4a-40=0

We move all terms containing a to the left, all other terms to the right

4a=40

a=40/4

a=10

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