4(3a+5)=7(4-a)

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Solution for 4(3a+5)=7(4-a) equation: 



4(3a+5)=7(4-a)

We move all terms to the left:

4(3a+5)-(7(4-a))=0

We add all the numbers together, and all the variables

4(3a+5)-(7(-1a+4))=0

We multiply parentheses

12a-(7(-1a+4))+20=0



We calculate terms in parentheses: -(7(-1a+4)), so:

7(-1a+4)

We multiply parentheses

-7a+28

Back to the equation:

-(-7a+28)



We get rid of parentheses

12a+7a-28+20=0

We add all the numbers together, and all the variables

19a-8=0

We move all terms containing a to the left, all other terms to the right

19a=8

a=8/19

a=8/19

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