4(3a+5)=7(4-a)

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Solution for 4(3a+5)=7(4-a) equation:



4(3a+5)=7(4-a)
We move all terms to the left:
4(3a+5)-(7(4-a))=0
We add all the numbers together, and all the variables
4(3a+5)-(7(-1a+4))=0
We multiply parentheses
12a-(7(-1a+4))+20=0
We calculate terms in parentheses: -(7(-1a+4)), so:
7(-1a+4)
We multiply parentheses
-7a+28
Back to the equation:
-(-7a+28)
We get rid of parentheses
12a+7a-28+20=0
We add all the numbers together, and all the variables
19a-8=0
We move all terms containing a to the left, all other terms to the right
19a=8
a=8/19
a=8/19

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