4(3a-1)=11a-3(a-4)

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Solution for 4(3a-1)=11a-3(a-4) equation: 



4(3a-1)=11a-3(a-4)

We move all terms to the left:

4(3a-1)-(11a-3(a-4))=0

We multiply parentheses

12a-(11a-3(a-4))-4=0



We calculate terms in parentheses: -(11a-3(a-4)), so:

11a-3(a-4)

We multiply parentheses

11a-3a+12

We add all the numbers together, and all the variables

8a+12

Back to the equation:

-(8a+12)



We get rid of parentheses

12a-8a-12-4=0

We add all the numbers together, and all the variables

4a-16=0

We move all terms containing a to the left, all other terms to the right

4a=16

a=16/4

a=4

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