4(3a-1)=3(4a-1)-4(3a-2)*

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Solution for 4(3a-1)=3(4a-1)-4(3a-2)* equation: 



4(3a-1)=3(4a-1)-4(3a-2)*

We move all terms to the left:

4(3a-1)-(3(4a-1)-4(3a-2)*)=0

We multiply parentheses

12a-(3(4a-1)-4(3a-2)*)-4=0



We calculate terms in parentheses: -(3(4a-1)-4(3a-2)*), so:

3(4a-1)-4(3a-2)*

We multiply parentheses

12a-12a-3+8

We add all the numbers together, and all the variables

5

Back to the equation:

-(5)



We add all the numbers together, and all the variables

12a-9=0

We move all terms containing a to the left, all other terms to the right

12a=9

a=9/12

a=3/4

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