4(3a-4)-3a=9(a-5)-5

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Solution for 4(3a-4)-3a=9(a-5)-5 equation: 



4(3a-4)-3a=9(a-5)-5

We move all terms to the left:

4(3a-4)-3a-(9(a-5)-5)=0

We add all the numbers together, and all the variables

-3a+4(3a-4)-(9(a-5)-5)=0

We multiply parentheses

-3a+12a-(9(a-5)-5)-16=0



We calculate terms in parentheses: -(9(a-5)-5), so:

9(a-5)-5

We multiply parentheses

9a-45-5

We add all the numbers together, and all the variables

9a-50

Back to the equation:

-(9a-50)



We add all the numbers together, and all the variables

9a-(9a-50)-16=0

We get rid of parentheses

9a-9a+50-16=0

We add all the numbers together, and all the variables

34!=0

There is no solution for this equation

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