4(3a-4)=10+8

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Solution for 4(3a-4)=10+8 equation: 



4(3a-4)=10+8

We move all terms to the left:

4(3a-4)-(10+8)=0

We add all the numbers together, and all the variables

4(3a-4)-18=0

We multiply parentheses

12a-16-18=0

We add all the numbers together, and all the variables

12a-34=0

We move all terms containing a to the left, all other terms to the right

12a=34

a=34/12

a=2+5/6

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