4(3b+2)=3(5+4b)+7b

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Solution for 4(3b+2)=3(5+4b)+7b equation: 



4(3b+2)=3(5+4b)+7b

We move all terms to the left:

4(3b+2)-(3(5+4b)+7b)=0

We add all the numbers together, and all the variables

4(3b+2)-(3(4b+5)+7b)=0

We multiply parentheses

12b-(3(4b+5)+7b)+8=0



We calculate terms in parentheses: -(3(4b+5)+7b), so:

3(4b+5)+7b

We add all the numbers together, and all the variables

7b+3(4b+5)

We multiply parentheses

7b+12b+15

We add all the numbers together, and all the variables

19b+15

Back to the equation:

-(19b+15)



We get rid of parentheses

12b-19b-15+8=0

We add all the numbers together, and all the variables

-7b-7=0

We move all terms containing b to the left, all other terms to the right

-7b=7

b=7/-7

b=-1

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