4(3b+2)=3(5+4b)+7b

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Solution for 4(3b+2)=3(5+4b)+7b equation:



4(3b+2)=3(5+4b)+7b
We move all terms to the left:
4(3b+2)-(3(5+4b)+7b)=0
We add all the numbers together, and all the variables
4(3b+2)-(3(4b+5)+7b)=0
We multiply parentheses
12b-(3(4b+5)+7b)+8=0
We calculate terms in parentheses: -(3(4b+5)+7b), so:
3(4b+5)+7b
We add all the numbers together, and all the variables
7b+3(4b+5)
We multiply parentheses
7b+12b+15
We add all the numbers together, and all the variables
19b+15
Back to the equation:
-(19b+15)
We get rid of parentheses
12b-19b-15+8=0
We add all the numbers together, and all the variables
-7b-7=0
We move all terms containing b to the left, all other terms to the right
-7b=7
b=7/-7
b=-1

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