4(3b+5)+b=6(2b+3)

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Solution for 4(3b+5)+b=6(2b+3) equation: 



4(3b+5)+b=6(2b+3)

We move all terms to the left:

4(3b+5)+b-(6(2b+3))=0

We add all the numbers together, and all the variables

b+4(3b+5)-(6(2b+3))=0

We multiply parentheses

b+12b-(6(2b+3))+20=0



We calculate terms in parentheses: -(6(2b+3)), so:

6(2b+3)

We multiply parentheses

12b+18

Back to the equation:

-(12b+18)



We add all the numbers together, and all the variables

13b-(12b+18)+20=0

We get rid of parentheses

13b-12b-18+20=0

We add all the numbers together, and all the variables

b+2=0

We move all terms containing b to the left, all other terms to the right

b=-2

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