4(3b-1)=2(4b+6)

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Solution for 4(3b-1)=2(4b+6) equation: 



4(3b-1)=2(4b+6)

We move all terms to the left:

4(3b-1)-(2(4b+6))=0

We multiply parentheses

12b-(2(4b+6))-4=0



We calculate terms in parentheses: -(2(4b+6)), so:

2(4b+6)

We multiply parentheses

8b+12

Back to the equation:

-(8b+12)



We get rid of parentheses

12b-8b-12-4=0

We add all the numbers together, and all the variables

4b-16=0

We move all terms containing b to the left, all other terms to the right

4b=16

b=16/4

b=4

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