4(3b-1)=2(4b+6)

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Solution for 4(3b-1)=2(4b+6) equation:



4(3b-1)=2(4b+6)
We move all terms to the left:
4(3b-1)-(2(4b+6))=0
We multiply parentheses
12b-(2(4b+6))-4=0
We calculate terms in parentheses: -(2(4b+6)), so:
2(4b+6)
We multiply parentheses
8b+12
Back to the equation:
-(8b+12)
We get rid of parentheses
12b-8b-12-4=0
We add all the numbers together, and all the variables
4b-16=0
We move all terms containing b to the left, all other terms to the right
4b=16
b=16/4
b=4

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