4(3b-2)=68

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Solution for 4(3b-2)=68 equation:



4(3b-2)=68
We move all terms to the left:
4(3b-2)-(68)=0
We multiply parentheses
12b-8-68=0
We add all the numbers together, and all the variables
12b-76=0
We move all terms containing b to the left, all other terms to the right
12b=76
b=76/12
b=6+1/3

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