4(3b-2)=68

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Solution for 4(3b-2)=68 equation: 



4(3b-2)=68

We move all terms to the left:

4(3b-2)-(68)=0

We multiply parentheses

12b-8-68=0

We add all the numbers together, and all the variables

12b-76=0

We move all terms containing b to the left, all other terms to the right

12b=76

b=76/12

b=6+1/3

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