4(3b-3)=-6+6b

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Solution for 4(3b-3)=-6+6b equation: 



4(3b-3)=-6+6b

We move all terms to the left:

4(3b-3)-(-6+6b)=0

We add all the numbers together, and all the variables

4(3b-3)-(6b-6)=0

We multiply parentheses

12b-(6b-6)-12=0

We get rid of parentheses

12b-6b+6-12=0

We add all the numbers together, and all the variables

6b-6=0

We move all terms containing b to the left, all other terms to the right

6b=6

b=6/6

b=1

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