4(3c+1)+2=3(2c+2)+6

Solution for 4(3c+1)+2=3(2c+2)+6 equation:

Simplifying
4(3c + 1) + 2 = 3(2c + 2) + 6

Reorder the terms:
4(1 + 3c) + 2 = 3(2c + 2) + 6
(1 * 4 + 3c * 4) + 2 = 3(2c + 2) + 6
(4 + 12c) + 2 = 3(2c + 2) + 6

Reorder the terms:
4 + 2 + 12c = 3(2c + 2) + 6

Combine like terms: 4 + 2 = 6
6 + 12c = 3(2c + 2) + 6

Reorder the terms:
6 + 12c = 3(2 + 2c) + 6
6 + 12c = (2 * 3 + 2c * 3) + 6
6 + 12c = (6 + 6c) + 6

Reorder the terms:
6 + 12c = 6 + 6 + 6c

Combine like terms: 6 + 6 = 12
6 + 12c = 12 + 6c

Solving
6 + 12c = 12 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
6 + 12c + -6c = 12 + 6c + -6c

Combine like terms: 12c + -6c = 6c
6 + 6c = 12 + 6c + -6c

Combine like terms: 6c + -6c = 0
6 + 6c = 12 + 0
6 + 6c = 12

Add '-6' to each side of the equation.
6 + -6 + 6c = 12 + -6

Combine like terms: 6 + -6 = 0
0 + 6c = 12 + -6
6c = 12 + -6

Combine like terms: 12 + -6 = 6
6c = 6

Divide each side by '6'.
c = 1

Simplifying
c = 1