4(3c+10)=12c+40

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Solution for 4(3c+10)=12c+40 equation: 



4(3c+10)=12c+40

We move all terms to the left:

4(3c+10)-(12c+40)=0

We multiply parentheses

12c-(12c+40)+40=0

We get rid of parentheses

12c-12c-40+40=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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