4(3c+4)=6(c+2)

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Solution for 4(3c+4)=6(c+2) equation: 



4(3c+4)=6(c+2)

We move all terms to the left:

4(3c+4)-(6(c+2))=0

We multiply parentheses

12c-(6(c+2))+16=0



We calculate terms in parentheses: -(6(c+2)), so:

6(c+2)

We multiply parentheses

6c+12

Back to the equation:

-(6c+12)



We get rid of parentheses

12c-6c-12+16=0

We add all the numbers together, and all the variables

6c+4=0

We move all terms containing c to the left, all other terms to the right

6c=-4

c=-4/6

c=-2/3

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