4(3c+4)=6(c+2)

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Solution for 4(3c+4)=6(c+2) equation:



4(3c+4)=6(c+2)
We move all terms to the left:
4(3c+4)-(6(c+2))=0
We multiply parentheses
12c-(6(c+2))+16=0
We calculate terms in parentheses: -(6(c+2)), so:
6(c+2)
We multiply parentheses
6c+12
Back to the equation:
-(6c+12)
We get rid of parentheses
12c-6c-12+16=0
We add all the numbers together, and all the variables
6c+4=0
We move all terms containing c to the left, all other terms to the right
6c=-4
c=-4/6
c=-2/3

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