4(3c+5)-12(c-3)=-c-3(c-4)

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Solution for 4(3c+5)-12(c-3)=-c-3(c-4) equation: 



4(3c+5)-12(c-3)=-c-3(c-4)

We move all terms to the left:

4(3c+5)-12(c-3)-(-c-3(c-4))=0

We multiply parentheses

12c-12c-(-c-3(c-4))+20+36=0



We calculate terms in parentheses: -(-c-3(c-4)), so:

-c-3(c-4)

We add all the numbers together, and all the variables

-1c-3(c-4)

We multiply parentheses

-1c-3c+12

We add all the numbers together, and all the variables

-4c+12

Back to the equation:

-(-4c+12)



We add all the numbers together, and all the variables

-(-4c+12)+56=0

We get rid of parentheses

4c-12+56=0

We add all the numbers together, and all the variables

4c+44=0

We move all terms containing c to the left, all other terms to the right

4c=-44

c=-44/4

c=-11

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