4(3c+5)=2(10-c)

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Solution for 4(3c+5)=2(10-c) equation: 



4(3c+5)=2(10-c)

We move all terms to the left:

4(3c+5)-(2(10-c))=0

We add all the numbers together, and all the variables

4(3c+5)-(2(-1c+10))=0

We multiply parentheses

12c-(2(-1c+10))+20=0



We calculate terms in parentheses: -(2(-1c+10)), so:

2(-1c+10)

We multiply parentheses

-2c+20

Back to the equation:

-(-2c+20)



We get rid of parentheses

12c+2c-20+20=0

We add all the numbers together, and all the variables

14c=0

c=0/14

c=0

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