4(3c-1)-6=10c+6

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Solution for 4(3c-1)-6=10c+6 equation: 



4(3c-1)-6=10c+6

We move all terms to the left:

4(3c-1)-6-(10c+6)=0

We multiply parentheses

12c-(10c+6)-4-6=0

We get rid of parentheses

12c-10c-6-4-6=0

We add all the numbers together, and all the variables

2c-16=0

We move all terms containing c to the left, all other terms to the right

2c=16

c=16/2

c=8

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