4(3c-1)-6=8c+2

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Solution for 4(3c-1)-6=8c+2 equation:


Simplifying
4(3c + -1) + -6 = 8c + 2

Reorder the terms:
4(-1 + 3c) + -6 = 8c + 2
(-1 * 4 + 3c * 4) + -6 = 8c + 2
(-4 + 12c) + -6 = 8c + 2

Reorder the terms:
-4 + -6 + 12c = 8c + 2

Combine like terms: -4 + -6 = -10
-10 + 12c = 8c + 2

Reorder the terms:
-10 + 12c = 2 + 8c

Solving
-10 + 12c = 2 + 8c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8c' to each side of the equation.
-10 + 12c + -8c = 2 + 8c + -8c

Combine like terms: 12c + -8c = 4c
-10 + 4c = 2 + 8c + -8c

Combine like terms: 8c + -8c = 0
-10 + 4c = 2 + 0
-10 + 4c = 2

Add '10' to each side of the equation.
-10 + 10 + 4c = 2 + 10

Combine like terms: -10 + 10 = 0
0 + 4c = 2 + 10
4c = 2 + 10

Combine like terms: 2 + 10 = 12
4c = 12

Divide each side by '4'.
c = 3

Simplifying
c = 3

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