4(3c-5)=5(2c+4)

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Solution for 4(3c-5)=5(2c+4) equation:


Simplifying
4(3c + -5) = 5(2c + 4)

Reorder the terms:
4(-5 + 3c) = 5(2c + 4)
(-5 * 4 + 3c * 4) = 5(2c + 4)
(-20 + 12c) = 5(2c + 4)

Reorder the terms:
-20 + 12c = 5(4 + 2c)
-20 + 12c = (4 * 5 + 2c * 5)
-20 + 12c = (20 + 10c)

Solving
-20 + 12c = 20 + 10c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10c' to each side of the equation.
-20 + 12c + -10c = 20 + 10c + -10c

Combine like terms: 12c + -10c = 2c
-20 + 2c = 20 + 10c + -10c

Combine like terms: 10c + -10c = 0
-20 + 2c = 20 + 0
-20 + 2c = 20

Add '20' to each side of the equation.
-20 + 20 + 2c = 20 + 20

Combine like terms: -20 + 20 = 0
0 + 2c = 20 + 20
2c = 20 + 20

Combine like terms: 20 + 20 = 40
2c = 40

Divide each side by '2'.
c = 20

Simplifying
c = 20

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