4(3d+1)=2(d-3)

Solution for 4(3d+1)=2(d-3) equation:

Simplifying
4(3d + 1) = 2(d + -3)

Reorder the terms:
4(1 + 3d) = 2(d + -3)
(1 * 4 + 3d * 4) = 2(d + -3)
(4 + 12d) = 2(d + -3)

Reorder the terms:
4 + 12d = 2(-3 + d)
4 + 12d = (-3 * 2 + d * 2)
4 + 12d = (-6 + 2d)

Solving
4 + 12d = -6 + 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
4 + 12d + -2d = -6 + 2d + -2d

Combine like terms: 12d + -2d = 10d
4 + 10d = -6 + 2d + -2d

Combine like terms: 2d + -2d = 0
4 + 10d = -6 + 0
4 + 10d = -6

Add '-4' to each side of the equation.
4 + -4 + 10d = -6 + -4

Combine like terms: 4 + -4 = 0
0 + 10d = -6 + -4
10d = -6 + -4

Combine like terms: -6 + -4 = -10
10d = -10

Divide each side by '10'.
d = -1

Simplifying
d = -1