4(3d+1)=4(2d+3)

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Solution for 4(3d+1)=4(2d+3) equation: 



4(3d+1)=4(2d+3)

We move all terms to the left:

4(3d+1)-(4(2d+3))=0

We multiply parentheses

12d-(4(2d+3))+4=0



We calculate terms in parentheses: -(4(2d+3)), so:

4(2d+3)

We multiply parentheses

8d+12

Back to the equation:

-(8d+12)



We get rid of parentheses

12d-8d-12+4=0

We add all the numbers together, and all the variables

4d-8=0

We move all terms containing d to the left, all other terms to the right

4d=8

d=8/4

d=2

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