4(3d+1)=5(6D-1)

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Solution for 4(3d+1)=5(6D-1) equation: 



4(3d+1)=5(6-1)

We move all terms to the left:

4(3d+1)-(5(6-1))=0

We add all the numbers together, and all the variables

4(3d+1)-(55)=0

We add all the numbers together, and all the variables

4(3d+1)-55=0

We multiply parentheses

12d+4-55=0

We add all the numbers together, and all the variables

12d-51=0

We move all terms containing d to the left, all other terms to the right

12d=51

d=51/12

d=4+1/4

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