4(3d+23)=12+32d

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Solution for 4(3d+23)=12+32d equation: 



4(3d+23)=12+32d

We move all terms to the left:

4(3d+23)-(12+32d)=0

We add all the numbers together, and all the variables

4(3d+23)-(32d+12)=0

We multiply parentheses

12d-(32d+12)+92=0

We get rid of parentheses

12d-32d-12+92=0

We add all the numbers together, and all the variables

-20d+80=0

We move all terms containing d to the left, all other terms to the right

-20d=-80

d=-80/-20

d=+4

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