4(3d-2)=6(d+4)

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Solution for 4(3d-2)=6(d+4) equation: 



4(3d-2)=6(d+4)

We move all terms to the left:

4(3d-2)-(6(d+4))=0

We multiply parentheses

12d-(6(d+4))-8=0



We calculate terms in parentheses: -(6(d+4)), so:

6(d+4)

We multiply parentheses

6d+24

Back to the equation:

-(6d+24)



We get rid of parentheses

12d-6d-24-8=0

We add all the numbers together, and all the variables

6d-32=0

We move all terms containing d to the left, all other terms to the right

6d=32

d=32/6

d=5+1/3

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