4(3f-12)=4(4f+8)

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Solution for 4(3f-12)=4(4f+8) equation: 



4(3f-12)=4(4f+8)

We move all terms to the left:

4(3f-12)-(4(4f+8))=0

We multiply parentheses

12f-(4(4f+8))-48=0



We calculate terms in parentheses: -(4(4f+8)), so:

4(4f+8)

We multiply parentheses

16f+32

Back to the equation:

-(16f+32)



We get rid of parentheses

12f-16f-32-48=0

We add all the numbers together, and all the variables

-4f-80=0

We move all terms containing f to the left, all other terms to the right

-4f=80

f=80/-4

f=-20

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