4(3g+5)=12g+20

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Solution for 4(3g+5)=12g+20 equation: 



4(3g+5)=12g+20

We move all terms to the left:

4(3g+5)-(12g+20)=0

We multiply parentheses

12g-(12g+20)+20=0

We get rid of parentheses

12g-12g-20+20=0

We add all the numbers together, and all the variables

=0

g=0/1

g=0

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