4(3j+2)=8(2j-1)

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Solution for 4(3j+2)=8(2j-1) equation:



4(3j+2)=8(2j-1)
We move all terms to the left:
4(3j+2)-(8(2j-1))=0
We multiply parentheses
12j-(8(2j-1))+8=0
We calculate terms in parentheses: -(8(2j-1)), so:
8(2j-1)
We multiply parentheses
16j-8
Back to the equation:
-(16j-8)
We get rid of parentheses
12j-16j+8+8=0
We add all the numbers together, and all the variables
-4j+16=0
We move all terms containing j to the left, all other terms to the right
-4j=-16
j=-16/-4
j=+4

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