4(3m+1)-2(2m+3)=3(m+4)+2m+7.

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Solution for 4(3m+1)-2(2m+3)=3(m+4)+2m+7. equation: 



4(3m+1)-2(2m+3)=3(m+4)+2m+7.

We move all terms to the left:

4(3m+1)-2(2m+3)-(3(m+4)+2m+7.)=0

We multiply parentheses

12m-4m-(3(m+4)+2m+7.)+4-6=0



We calculate terms in parentheses: -(3(m+4)+2m+7.), so:

3(m+4)+2m+7.

We add all the numbers together, and all the variables

2m+3(m+4)+7

We multiply parentheses

2m+3m+12+7

We add all the numbers together, and all the variables

5m+19

Back to the equation:

-(5m+19)



We add all the numbers together, and all the variables

8m-(5m+19)-2=0

We get rid of parentheses

8m-5m-19-2=0

We add all the numbers together, and all the variables

3m-21=0

We move all terms containing m to the left, all other terms to the right

3m=21

m=21/3

m=7

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